The line has a slope of 3 because
y = mx+b where m is the slope.
Perpendicular lines have slopes that are negative reciprocals.
So we have a 3 which makes our perp line's slope -1/3
If you multiply the two slopes you will always get a -1 if the lines are perpendicular If the lines are parallel the slopes are the same.
Now, you have the slop -1/3 and a point (3, 4).
There are couple different ways to get your line.
one way is to use y = mx+b
4 = (-1/3)(3) + b
4 = -1 + b
5 = b
you have m=-1/3 and b =5
y = mx + b
y = -1/3 x + b
Write the equation of the line perpendicular to the given line and passing through the given point: y=3x−2 through (3,4)
this problem is really hard for me
can you please show and tell how you got your answers
thanks,:)
1 answer
1 answer