To find the equation of the line in slope-intercept form (y = mx + b) that passes through the points (0, 2.3) and (5, -1.9), we need to calculate the slope (m) first.
The formula for the slope (m) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Substituting the points (0, 2.3) as \((x_1, y_1)\) and (5, -1.9) as \((x_2, y_2)\):
\[ m = \frac{-1.9 - 2.3}{5 - 0} = \frac{-4.2}{5} = -0.84 \]
Now that we have the slope \(m = -0.84\), we can use the point (0, 2.3) to find the y-intercept \(b\). Since the x-coordinate is 0 at this point, the y-coordinate is the y-intercept:
\[ b = 2.3 \]
Now we can write the equation of the line in slope-intercept form:
\[ y = mx + b \]
Substituting in the values we've found:
\[ y = -0.84x + 2.3 \]
So the equation in slope-intercept form is:
\[ \boxed{y = -0.84x + 2.3} \]
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