Write the equation of the line in either point-slope form or slope-intercept form.

Question

Write the equation of a line that has a slope of -3 and passes through the point (1.25, -4).

Use the drop-down menus to select the appropriate values in the equation.

y =
x
+

Answer 1

To write the equation of the line in slope-intercept form (y = mx + b), we can use the given slope and the point it passes through.

Here, we have:

• Slope (m) = -3
• Point (1.25, -4)

We can substitute the slope and the point into the slope-intercept form equation to find the y-intercept (b).

1. Start with the slope-intercept form: \[ y = mx + b \]

2. Plug in the slope and the coordinates of the point (x, y): \[ -4 = -3(1.25) + b \]

3. Calculate -3(1.25): \[ -3(1.25) = -3.75 \]

4. Now plug that back into the equation: \[ -4 = -3.75 + b \]

5. Solving for b: \[ b = -4 + 3.75 \] \[ b = -0.25 \]

Now that we have the slope and the y-intercept, we can write the equation of the line:

\[ y = -3x - 0.25 \]

In the context of the drop-down menu values:

• The slope (m) is -3,
• The y-intercept (b) is -0.25.

So the values would be:

y = -3x + (-0.25)