Write the equation of lines tangent and normal to the following function at (0, π). To find derivative, use implicit differentiation.

Question

x^2cos^y - siny = 0

Answer 1

I do not know what cos^y means. I'll just use cosy and you can fix it as needed.

x^2 cosy - siny = 0
2x cosy - x^2 siny y' - cosy y' = 0
y' = (2x cosy)/(x^2 siny + cosy)

so, at (0,π), y' = 0
Since the tangent is horontal, the normal is vertical, and the lines are

tangent: y=π
normal: x=0