x = -5 is a vertical line.
So, you want a horizontal line through (-3,-7)
Now, what might that be?
Write the equation of a line that is perpendicular to the line x = -5 and passes through the point (-3,-7)
5 answers
(-5,-7)????
(-3,-7), (-5,-7).
m = (-7-(-7))/(-5-(-3)) = 0/-2 = 0.
Y = mx + b = -7.
0*x + b = -7, b = -7,
Eq: Y = -7 = A horizontal line.
m = (-7-(-7))/(-5-(-3)) = 0/-2 = 0.
Y = mx + b = -7.
0*x + b = -7, b = -7,
Eq: Y = -7 = A horizontal line.
Or, just note that a horizontal line is expressed by the equation
y = k
for some k. Since we have the point (-3,-7), the line is just
y = -7
y = k
for some k. Since we have the point (-3,-7), the line is just
y = -7
Right!