Write the equation of a line that is perpendicular to the line x = -5 and passes through the point (-3,-7)

5 answers

x = -5 is a vertical line.

So, you want a horizontal line through (-3,-7)

Now, what might that be?
(-5,-7)????
(-3,-7), (-5,-7).

m = (-7-(-7))/(-5-(-3)) = 0/-2 = 0.

Y = mx + b = -7.
0*x + b = -7, b = -7,
Eq: Y = -7 = A horizontal line.
Or, just note that a horizontal line is expressed by the equation

y = k

for some k. Since we have the point (-3,-7), the line is just

y = -7
Right!