The given equation is y = -1/2x - 13.
Since we want to find a line perpendicular to this equation, we know that the slope of the new line will be the negative reciprocal of the slope of the given line. The given line has a slope of -1/2, so the new line will have a slope of 2.
Now, we have the slope of the new line (m = 2) and a point it passes through (1,7). We can use the point-slope form of a linear equation to find the equation of the line:
y - y₁ = m(x - x₁)
Substituting the values, we get:
y - 7 = 2(x - 1)
Expanding the equation, we have:
y - 7 = 2x - 2
To convert it to standard form, we move all the terms to the left side:
2x - y = 5
Therefore, the equation of the line in standard form that is perpendicular to y = -1/2x - 13 and passes through (1,7) is 2x - y = 5.
Write the equation of a line I’m STANDARD FORM that is perpendicular to y=-1/2-13 and passes through (1,7)
1 answer
1 answer