write the equation in standard form for the circle passing through (12,0) centered at the origin

Answer 1

First, we can find the radius of the circle using the distance formula:

r = sqrt((12-0)^2 + (0-0)^2) = 12

Next, we can use the standard form of the equation for a circle:

(x - h)^2 + (y - k)^2 = r^2

where (h,k) is the center of the circle and r is the radius.

In this case, the center is at the origin (0,0), so we can simplify the equation to:

x^2 + y^2 = r^2

Substituting r = 12, we get:

x^2 + y^2 = 144

So the standard form of the equation for the circle passing through (12,0) centered at the origin is:

x^2 + y^2 = 144