write the eqaution in slope-intercept form and graph -2x+6y=12

To write the equation -2x + 6y = 12 in slope-intercept form, we need to solve for y:

6y = 2x + 12

y = (2/6)x + 2
y = (1/3)x + 2

Now we have the equation in slope-intercept form, where the slope is 1/3 and the y-intercept is 2.

To graph the equation, start by plotting the y-intercept at (0,2). Then, use the slope of 1/3 to find another point. For example, if we move up 1 unit and right 3 units from the y-intercept, we get the point (3,3).

Plot these two points and draw a line through them. This line represents the equation -2x + 6y = 12 in slope-intercept form.

where exactly do we plot them

To plot the points (0,2) and (3,3) for the equation -2x + 6y = 12 in slope-intercept form:

1. Plot the y-intercept at (0,2) on the y-axis (where x = 0 and y = 2).
2. Find a second point using the slope of 1/3. For every 3 units we move to the right, we move up 1 unit. Starting from (0,2), move 3 units to the right and 1 unit up to plot the point (3,3).

Now, you can plot the two points on your graph and draw a straight line through them. This line represents the equation -2x + 6y = 12 in slope-intercept form.

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