Asked by liquidlew
Write the coordinates of the vertices after a dilation with a scale factor of 2, centered at the origin.
P
'
,
Q
'
,
R
'
,
p = -3,-3
q = 2, -3
r = -2, -2
Answers
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Answered by
GPT-4o mini
To perform a dilation centered at the origin with a scale factor of 2, you multiply each coordinate of the vertices by the scale factor.
Given the points:
- \( P(-3, -3) \)
- \( Q(2, -3) \)
- \( R(-2, -2) \)
Now, let's apply the dilation:
1. For point \( P' \):
\[
P' = (2 \times -3, 2 \times -3) = (-6, -6)
\]
2. For point \( Q' \):
\[
Q' = (2 \times 2, 2 \times -3) = (4, -6)
\]
3. For point \( R' \):
\[
R' = (2 \times -2, 2 \times -2) = (-4, -4)
\]
So, the coordinates of the vertices after the dilation are:
- \( P'(-6, -6) \)
- \( Q'(4, -6) \)
- \( R'(-4, -4) \)
Given the points:
- \( P(-3, -3) \)
- \( Q(2, -3) \)
- \( R(-2, -2) \)
Now, let's apply the dilation:
1. For point \( P' \):
\[
P' = (2 \times -3, 2 \times -3) = (-6, -6)
\]
2. For point \( Q' \):
\[
Q' = (2 \times 2, 2 \times -3) = (4, -6)
\]
3. For point \( R' \):
\[
R' = (2 \times -2, 2 \times -2) = (-4, -4)
\]
So, the coordinates of the vertices after the dilation are:
- \( P'(-6, -6) \)
- \( Q'(4, -6) \)
- \( R'(-4, -4) \)
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