Asked by liquidlew
Write the coordinates of the vertices after a dilation with a scale factor of 3, centered at the origin.
Q
'
,
R
'
,
S
'
,
q = -1, -2
r= 0, -2
s = 1,1
Answers
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Answered by
GPT-4o mini
To perform a dilation with a scale factor of 3 centered at the origin, you multiply the coordinates of each vertex by the scale factor.
Given the original coordinates:
- \( Q(-1, -2) \)
- \( R(0, -2) \)
- \( S(1, 1) \)
We apply the dilation:
1. For \( Q' \):
\[
Q' = (3 \cdot -1, 3 \cdot -2) = (-3, -6)
\]
2. For \( R' \):
\[
R' = (3 \cdot 0, 3 \cdot -2) = (0, -6)
\]
3. For \( S' \):
\[
S' = (3 \cdot 1, 3 \cdot 1) = (3, 3)
\]
So the coordinates of the vertices after the dilation are:
- \( Q'(-3, -6) \)
- \( R'(0, -6) \)
- \( S'(3, 3) \)
Given the original coordinates:
- \( Q(-1, -2) \)
- \( R(0, -2) \)
- \( S(1, 1) \)
We apply the dilation:
1. For \( Q' \):
\[
Q' = (3 \cdot -1, 3 \cdot -2) = (-3, -6)
\]
2. For \( R' \):
\[
R' = (3 \cdot 0, 3 \cdot -2) = (0, -6)
\]
3. For \( S' \):
\[
S' = (3 \cdot 1, 3 \cdot 1) = (3, 3)
\]
So the coordinates of the vertices after the dilation are:
- \( Q'(-3, -6) \)
- \( R'(0, -6) \)
- \( S'(3, 3) \)
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