Write the coordinates of the vertices after a dilation with a scale factor of

1
2
, centered at the origin.
R'
,
S'
,
T'
,
U'
,

5 answers

Given the original coordinates of the vertices:
R(2, 4)
S(6, 4)
T(6, 2)
U(2, 2)

After a dilation with a scale factor of 1/2 centered at the origin, the new coordinates would be:
R'(1, 2)
S'(3, 2)
T'(3, 1)
U'(1, 1)
5 ft. 13ft.
What is the length of the missing leg? If necessary, round to the nearest tenth.
a=
feet
To find the length of the missing leg of a right triangle given the other two sides, you can use the Pythagorean Theorem, which states that a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the other two sides.

Given:
a = 5 ft
b = 13 ft

Let's assume the missing leg is represented by c.

So, using the Pythagorean theorem:
5^2 + 13^2 = c^2
25 + 169 = c^2
194 = c^2
c = sqrt(194)
c ≈ 13.9 (rounded to the nearest tenth)

Therefore, the length of the missing leg is approximately 13.9 feet.
Evaluate the expression.
(

0.9–

1)÷(

0.3+0.2)
Write your answer as an integer or a decimal. Do not round.
To evaluate the expression (-0.9 - (-1)) ÷ (-0.3 + 0.2), we first simplify the numerator and denominator separately:

(-0.9 - (-1)) = -0.9 + 1 = 0.1
(-0.3 + 0.2) = -0.1

Now, we divide the numerator by the denominator:
0.1 ÷ -0.1 = -1

Therefore, the evaluation of the expression is -1.