Since i=sqrt(-1), we can suggest
i=(-1)^(1/2) in exponent form.
Also, since
e^(ix)=cos(x) + i*sin(x)
we put x=π/2 to get
e^(iπ/2)
= cos(π/2) + i*sin(π/2)
= 0 + i*1
=i
However, i is also on the left-hand expression, so it is probably not the answer sought after.
Write the complex number in exponential form.
i
i is the complex number.
1 answer