Write the complete ionic equation for

Question

BaCl2 + NaOH ---->

Al2(SO4)3 + BaCl2 --->

Al2(SO4)3 + NaOH --->

NaOH + Zn(No3)2 --->

BaCl2 + NaI --->

Answer 1

I will do one. First one products would be Ba(OH2), but that is insoluble, a reaction occurs. NaCL...that is soluble, no reaction
Net Ionic:
Ba++ + 2OH->> Ba(OH)2 (s)
Complete Ionic:
Ba²⁺ + 2Cl^- + 2Na⁺ + 2OH^- >> Ba(OH)₂ (s) + 2Na⁺ + 2Cl^-