Write the chemical reaction of lithium metal in a solution of silver nitrate. Indicate the charge of each species. Clearly indicate which metal is undergoing oxidation and which metal is undergoing reduction. State which ion is the spectator ion. Explain how you arrived at your answers.

Answer 1

The molecular equation is this.
Li(s) + AgNO3(aq) ==> LiNO3(aq) + Ag(s)
The complete ionic equation is this.
Li(s) + Ag^+(aq) + NO3^-(aq) ==> Li^+(aq) + NO3^-(aq) + Ag(s)
Cancel the ions common to both sides to leave the net ionic equation. The ion you cancel is the spectator ion.
Li(s) + Ag^+(aq) ==> Li^+(aq) + Ag(s)
Oxidation is the loss of electrons; reduction is the gain of electrons. Li metal goes from oxidation state of 0 to +1; Ag goes from +1 to 0. You take it from there.
Post your work if you have questions.

Answer 2

What type of reaction would this be tho? Synthesis, double displacement, single displacement, etc...