In 300.0 mL of a 0.50 M MgCl2 solution, what would be the concentration of the chloride ions?
(MgCl2) is 0.50 M.
There are two Cl^- for each MgCl2; therefore, the Cl will be twice the MgCl2.
The equation for part a is correct.
Write the balanced dissociation equation for MgCl2. (1 mark)
MgCl2(s) + H2O(l) ==> Mg^+2(aq) + 2Cl^-(aq)
b) In 300.0 mL of a 0.50 M MgCl2 solution, what would be the concentration of the chloride ions?
1 answer