write in order from least to greatest the six numbers whose digits are 2, 8 and 9

Answer 1

To list the six numbers that can be formed using the digits 2, 8, and 9, we consider all possible combinations of these digits, utilizing each digit exactly once. The possible three-digit numbers are:

1. 289
2. 298
3. 829
4. 892
5. 928
6. 982

Now, we can order these numbers from least to greatest:

1. 289
2. 298
3. 829
4. 892
5. 928
6. 982

Thus, the final order from least to greatest is: 289, 298, 829, 892, 928, 982.