Write each power as radical
1. 12^1/4
2. (-50)^5/3
3 answers
we've done a bunch of these -- how about you take a stab at these first?
I'm don't get it man My brain is fried
12^(1/4) = ∜12
(-50)^(5/3) = ∛(-50)^5
just remember that the nth root is the 1/n power
since
∛x * ∛x * ∛x = ∛x^3 = x,
expressed as powers, you need
x^(1/3) * x^(1/3) * x^(1/3)
= x^(1/3 + 1/3 + 1/3)
= x^1
= x
(-50)^(5/3) = ∛(-50)^5
just remember that the nth root is the 1/n power
since
∛x * ∛x * ∛x = ∛x^3 = x,
expressed as powers, you need
x^(1/3) * x^(1/3) * x^(1/3)
= x^(1/3 + 1/3 + 1/3)
= x^1
= x
1 answer