assuming all logs are in base 4, we have
log 3 + log √8 - log 2
= log(3√8/2)
= log(3√2)
If, for some reason you are using logs base 10, and all the numbers are the values, then we have
log 4^3 + log 4^4 - log 4^2
= log(4^3*4^4/4^2)
= log(4^5)
= log(1024)
Write each expression as a single logarithm
I need help really fast. I have to finish this by today.
log4^3 + 1/2log4^8 - log4^2
1 answer