Asked by Victoria
Write each equation in standard form. Solve by using the Quadratic Formula.
1. -7 = x^2
A: ?
2. x^2 - 16 = 0
A: x = 4 or x = -4.
1. -7 = x^2
A: ?
2. x^2 - 16 = 0
A: x = 4 or x = -4.
Answers
Answered by
Reiny
anything squared cannot be negative in the real number set, so your first one has no real number solution
2. correct
2. correct
Answered by
Damon
x^2 + 0 x + 7 = 0
x = [ 0 +/- sqrt(-28) ]/2
x = +/- 2 sqrt -7/2
x = +/- sqrt(-7) or +/- i sqrt 7
=================================
x^2 - 0 x -16 = 0
x = [ 0 + /- sqrt (0 +4*16) ]/2
x = +/- 2*4/2
x = +/- 4
what else is new :)
x = [ 0 +/- sqrt(-28) ]/2
x = +/- 2 sqrt -7/2
x = +/- sqrt(-7) or +/- i sqrt 7
=================================
x^2 - 0 x -16 = 0
x = [ 0 + /- sqrt (0 +4*16) ]/2
x = +/- 2*4/2
x = +/- 4
what else is new :)
Answered by
Victoria
Are you sure? I haven't written the equation in standard form yet.
1. x^2 + 0x + 7 = 0
1. x^2 + 0x + 7 = 0
Answered by
Damon
Yes, the only solutions to the first problem are the imaginary numbers +/- i sqrt 7
where i is the sqrt of NEGATVE one
where i is the sqrt of NEGATVE one
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