we know that PV = kT, so PV/T remains constant
So, let's assume that he needs 1 volume unit of air below. That means we need to find the volume on the mt top.
760*1/(273+18) = 240V/(273+5)
V = 3.025
So, he will need about 3 times as much air at the higher elevation.
Write down the ideal gas equation.A mantakes 16breaths per minute at 18degree cencus and 760mmHg.what is his rate of breathing on a mountain-top where the temperature is 5degree cencus and the pressure is 240mmHg.assume that he needsthe same mass of air per minute.
1 answer