To write \((-x^2 y^3 m)^5\) as a monomial in standard form, we can use the rule of exponents \((a^m)^n = a^{m \cdot n}\) for each component inside the parentheses:
\[ (-x^2 y^3 m)^5 = (-1)^5 (x^2)^5 (y^3)^5 (m)^5 \]
Calculating each component:
- \((-1)^5 = -1\)
- \((x^2)^5 = x^{2 \cdot 5} = x^{10}\)
- \((y^3)^5 = y^{3 \cdot 5} = y^{15}\)
- \(m^5 = m^5\)
Putting it all together, we have:
\[ (-x^2 y^3 m)^5 = -1 \cdot x^{10} \cdot y^{15} \cdot m^5 \]
Thus, the final expression in standard form as a monomial is:
\[ -\ x^{10} y^{15} m^5 \]