In direct variation, we express the relationship between \( y \) and \( x \) with the equation \( y = kx \), where \( k \) is the constant of variation.
- First, we know that \( y = 5 \) when \( x = 55 \). We can substitute these values into the equation to find \( k \):
\[ 5 = k \cdot 55 \]
Now, solve for \( k \):
\[ k = \frac{5}{55} = \frac{1}{11} \]
So, the equation for the direct variation is:
\[ y = \frac{1}{11} x \]
- Now, we need to find the value of \( y \) when \( x = 22 \):
\[ y = \frac{1}{11} \cdot 22 \]
Calculate \( y \):
\[ y = \frac{22}{11} = 2 \]
Thus, when \( x = 22 \), \( y = 2 \).
The correct response is:
"When x=22, y=2."