In direct variation, the relationship between \( y \) and \( x \) can be expressed with the equation:
\[ y = kx \]
where \( k \) is the constant of variation.
We know that \( y = 5 \) when \( x = 55 \). We can use this information to find \( k \):
\[ 5 = k \cdot 55 \]
To solve for \( k \):
\[ k = \frac{5}{55} = \frac{1}{11} \]
Now we have the equation for the direct variation:
\[ y = \frac{1}{11}x \]
Next, we need to find the value of \( y \) when \( x = 22 \):
\[ y = \frac{1}{11} \cdot 22 \]
Calculating that gives:
\[ y = \frac{22}{11} = 2 \]
Thus, when \( x = 22 \), \( y = 2 \).
The correct response is:
When x=22, y=2.
When x equals 22, y equals 2.
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