Question 4: A rectangle has a length that is 5 more than twice the width. If the perimeter of the rectangle is 54 inches, find the dimensions of the rectangle.
Solution:
Let the width of the rectangle be "x" inches.
Then, the length of the rectangle is (2x + 5) inches.
The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width)
Substitute the given values into the formula:
54 = 2((2x + 5) + x)
Simplify the equation:
54 = 2(2x + 5 + x)
54 = 2(3x + 5)
54 = 6x + 10
44 = 6x
x = 44/6
x = 7.33
So, the width of the rectangle is approximately 7.33 inches.
The length of the rectangle is:
2(7.33) + 5
14.66 + 5
19.66 inches
Therefore, the dimensions of the rectangle are width = 7.33 inches and length = 19.66 inches.
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answers to Question 4
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