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write and equation for the reaction of triethylamine and water. does the eqilibrium go to the right or left.

so far what I have is C6H15N + H2O

but I'm not sure of the products

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Triethyl amine is a base; therefore, it accepts a proton (from H2O) which releases the OH^-
(CH3CH2)3N + HOH ==> (CH3CH2)3NH^+ + OH^-

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