Write an inverse variation equation, yequalsStartFraction k Over x EndFraction
, that satisfies the ordered pairs in the table.
x
10
one fourth
negative five fourths
y
0.025
1
negative one fifth
Question content area bottom
Part 1
yequals
enter your response here
(Simplify your answer. Use integers or decimals for any numbers in the expression.)
11 answers
y = 0.1x
inccorect
The correct inverse variation equation based on the given data is:
\[ y = \frac{1}{40}x \]
\[ y = \frac{1}{40}x \]
Write an inverse variation equation, yequalsStartFraction k Over x EndFraction
, that satisfies the ordered pairs in the table.
x
10
one half
negative five halves
y
0.05
1
negative one fifth
Question content area bottom
Part 1
yequals
enter your response here
(Simplify your answer. Use integers or decimals for any numbers in the expression.)
, that satisfies the ordered pairs in the table.
x
10
one half
negative five halves
y
0.05
1
negative one fifth
Question content area bottom
Part 1
yequals
enter your response here
(Simplify your answer. Use integers or decimals for any numbers in the expression.)
y = 0.1x
I SAID INCCORECT
I apologize for the oversight. Let's find the constant of variation (k) using the given values in the table.
The equation for inverse variation is: y = k/x.
From the table:
When x = 10, y = 0.05:
0.05 = k/10
k = 0.05 * 10
k = 0.5
Therefore, the inverse variation equation that satisfies the table is:
y = 0.5/x
The equation for inverse variation is: y = k/x.
From the table:
When x = 10, y = 0.05:
0.05 = k/10
k = 0.05 * 10
k = 0.5
Therefore, the inverse variation equation that satisfies the table is:
y = 0.5/x
INCCORECT YOU ARE WRONG
I apologize for the error in my responses. Let's correct this.
Given the ordered pairs are:
(10, 0.05),
(1/2, 1),
(-5/2, -1/5).
To find the constant of variation (k), we can use the formula y = k/x.
From the first ordered pair (10, 0.05):
0.05 = k/10,
k = 0.05 * 10 = 0.5.
Therefore, the inverse variation equation that satisfies the table is y = 0.5x.
Given the ordered pairs are:
(10, 0.05),
(1/2, 1),
(-5/2, -1/5).
To find the constant of variation (k), we can use the formula y = k/x.
From the first ordered pair (10, 0.05):
0.05 = k/10,
k = 0.05 * 10 = 0.5.
Therefore, the inverse variation equation that satisfies the table is y = 0.5x.
YOU ARE WRONG
I apologize for the errors in my previous responses. Let's correctly identify the inverse variation equation using the given values from the table.
Given values:
(10, 0.05),
(1/2, 1),
(-5/2, -1/5).
To find the constant of variation (k) in the equation y = k/x, we can use the second ordered pair (1/2, 1):
1 = k / (1/2),
1 = 2k,
k = 1/2.
Therefore, the correct inverse variation equation that satisfies the given table is:
y = (1/2) / x.
I apologize for the confusion in earlier responses and appreciate your patience.
Given values:
(10, 0.05),
(1/2, 1),
(-5/2, -1/5).
To find the constant of variation (k) in the equation y = k/x, we can use the second ordered pair (1/2, 1):
1 = k / (1/2),
1 = 2k,
k = 1/2.
Therefore, the correct inverse variation equation that satisfies the given table is:
y = (1/2) / x.
I apologize for the confusion in earlier responses and appreciate your patience.
5 answers