Write an inequality to represent this real-world situation. Andre wants to practice the piano 9 hours a week. Each time he practices he practices for 2/3 hour. If he has already practiced 2 hours this week, how many sessions, x , does he still need to practice to reach or surpass his goal?(1 point)

7 answers

2/3x + 2 ≥ 9, where x represents the number of sessions Andre still needs to practice.
so whats the answer?
To find the answer, we need to solve the inequality 2/3x + 2 ≥ 9 for x.

First, we can subtract 2 from both sides of the inequality:
2/3x + 2 - 2 ≥ 9 - 2
2/3x ≥ 7

Next, we can multiply both sides of the inequality by 3 to get rid of the fraction:
3 * (2/3x) ≥ 7 * 3
2x ≥ 21

Finally, we can divide both sides of the inequality by 2 to solve for x:
(2x) / 2 ≥ 21 / 2
x ≥ 10.5

Therefore, Andre still needs to practice at least 11 sessions to reach or surpass his goal of 9 hours of practice per week.
are you sure???
Apologies for the confusion in the previous response. Let's go through the solution again:

Andre wants to practice for 9 hours a week and each time he practices for 2/3 hour. He has already practiced 2 hours this week. We need to find how many more sessions, x, he needs to practice to reach or surpass his goal.

To solve this, we can set up the inequality:

2/3x + 2 ≥ 9

Now, let's solve it:

Subtract 2 from both sides:
2/3x + 2 - 2 ≥ 9 - 2
2/3x ≥ 7

Multiply both sides by 3 to remove the fraction:
3 * (2/3x) ≥ 7 * 3
2x ≥ 21

Divide both sides by 2 to solve for x:
(2x) / 2 ≥ 21 / 2
x ≥ 10.5

Since x represents the number of sessions Andre still needs to practice, we cannot have a fraction for it, so we need to round up the value of x to the nearest whole number.

Therefore, Andre still needs to practice at least 11 sessions to reach or surpass his goal of 9 hours of practice per week.
A bridge can hold a maximum of 75,000 pounds. A truck that weighs 40,000 pounds carries boxes that weigh 40 pounds each. What is the maximum number of boxes the truck can carry to cross the bridge? Express your answer as an inequality.
Let x represent the number of boxes the truck can carry.

Each box weighs 40 pounds, so the total weight of the boxes would be 40x pounds.

The weight of the truck and the boxes should not exceed the maximum weight the bridge can hold, which is 75,000 pounds.

Therefore, the inequality to represent this situation is:
40x + 40,000 ≤ 75,000.