Let's assume the number of trips to the park is represented by 'x'.
The cost of purchasing a season pass is $117.
The cost of paying daily admission is $39 * x.
We are asked to find the number of trips for which paying daily admission is three times more expensive than purchasing a season pass.
Mathematically, we can represent this using an inequality:
39x > 117 + 3 * 117
Simplifying the inequality:
39x > 117 + 351
39x > 468
To solve for x, divide both sides of the inequality by 39:
x > 468/39
x > 12
Therefore, the number of trips to the park for which paying daily admission is three times more expensive than purchasing a season pass is greater than 12.
Write an inequality and solve
A season pass to the amusement park costs $117, and haily admission costs $39. Determine the number of trips to the park for which paying daily admission is three times more expensive than purchasing a season past
1 answer
1 answer