Write an expression for the equilibrium constant for the formation of two moles of ammonia gas (NH3) from nitrogen

and hydrogen in their standard states.
N2(g) + 3 H2(g) 2 NH3(g)

1 answer

I assume this this the equation.
N2(g) + 3H2(g) ==> 2NH3(g)
Remember, equilibrium constant is product of the products divided by product of the reactants, each raised to the power indicated by the coefficients.
So Keq = (NH3)^2/(N2)(H2)^3