The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
Given that the point is (3, 5) and the slope is -4, we can substitute these values into the slope-intercept form to find the equation.
y = mx + b
5 = -4(3) + b
5 = -12 + b
Now, we can solve for b.
5 + 12 = b
17 = b
So, the equation of the line is y = -4x + 17.
Write an equation of the line through the given point with the given slope. Write the equation in slope-intercept form.
(3, 5); m = -4
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