Write an equation of the line that passes through the given points.

Question

​(negative 2
​,6​)
and ​(1
​,3
​)
Question content area bottom
Part 1
The equation is enter your response here
.
​(Type your answer in​ slope-intercept form.)

Answer 1

To find the equation of the line passing through the points (-2,6) and (1,3), we need to find the slope (m) and the y-intercept (b).

The slope (m) can be found using the slope formula:

m = (y2 - y1) / (x2 - x1)

Let's use the first point (-2,6) as (x1, y1) and the second point (1,3) as (x2, y2).

m = (3 - 6) / (1 - (-2))
m = -3 / 3
m = -1

Now, we can use the point-slope form of a linear equation using one of the given points (let's use the second point, (1,3)).

y - y1 = m(x - x1)
y - 3 = -1(x - 1)
y - 3 = -x + 1

Next, we can rearrange the equation to slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

y - 3 = -x + 1
y = -x + 4

Therefore, the equation of the line passing through (-2,6) and (1,3) is y = -x + 4.