the slope is (3+1)/(3-2) = 4
Now you have a point and a slope, so use the point-slope form of the line:
y+1 = 4(x-2)
write an equation of the line that passes through (2, -1) and (-3,3).
5 answers
what is the slope?
m = (3 - -1) / (-3 -2) = 4/-5 = -4/5
so
y = - 4 x/5 + b
put a point in
-1 = -8/5 + b
b = 8/5 - 5/5 = 3/5
so
y = -4x/5 +3/5
5 y = -4 x + 3
m = (3 - -1) / (-3 -2) = 4/-5 = -4/5
so
y = - 4 x/5 + b
put a point in
-1 = -8/5 + b
b = 8/5 - 5/5 = 3/5
so
y = -4x/5 +3/5
5 y = -4 x + 3
Thank you!
Oops. Pesky minus sign!
write an equation of the line that passes through (2, -1) and (-3,3).
write an equation of the line that passes through (2, -1) and (-3,3).
write an equation of the line that passes through (2, -1) and (-3,3).
11 answers