figure slope first.
slope first: 3y=8x-2, or y= 8/2 x=2/3
slope is 2/3
Then, the line
y= mx+b
y= 8/3 x +b put in (2,-4), and solve for b, thence you have the line.
write an equation of the line containing the given point and parallel to the given line (2,-4); 8x-3y=2 the equation of the line is y=
2 answers
since it is parallel to 8x - 3y = 2, the new line will differ only in the constant.
let the new line be 8x - 3y = c
plug in the given point (2,-4)
16 + 12 = c = 28
8x - 3y = 28
let the new line be 8x - 3y = c
plug in the given point (2,-4)
16 + 12 = c = 28
8x - 3y = 28