write an equation of the line containing the given point and parallel to the given line; use y=mx+b form; (5,8) x+4y=7 i keep getting this wrong. Can someone show me how to work this? Thank you so much

Answer 1

since the new line is parallel to the old line, their slopes must be the same, that is
the new equation must look like this

x+4y = c
plug in the new point (5,8)
5 + 32 = c
c = 37

so the new equation is x + 4y = 37

now change this to the form y = mx + b
4y = - x + 37
y = (-1/4)x + 37/4