a line parallel to y = 3x - 5 must look like
y = 3x + b, that is, it can only differ in the constant, the slope stays the same.
So we need to find that constant b.
But we know that (3,1) lies on it, so
in y = 3x + b
1 = 3(3) + b
b = -8
new equation: y = 3x - 8
Write an equation of a line that is parallel to y = 3x – 5 and goes through the point (3, 1).
1 answer