The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
To find the equation of a line that is parallel to the given equation, we know that the slope of the parallel line will be the same.
Given equation: y = -3x + 4
The slope of the given equation is -3. Therefore, the slope of the parallel line will also be -3.
We are also given a point that the line passes through: (-5, -6). We can substitute these coordinates into the slope-intercept form and solve for the y-intercept.
-6 = -3(-5) + b
-6 = 15 + b
b = -21
Now that we know the slope (-3) and the y-intercept (-21), we can write the equation of the line in slope-intercept form:
y = -3x - 21
Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(-5, -6); y = -3x + 4
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