Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. ; (1 point) Responses Image with alt text: y equals negative 2 x. Image with alt text: y equals 2 x. Image with alt text: y equals one-half x.

Answer 1

Since the line we want is parallel to the graph of the equation y = -2x, it will have the same slope as -2. We also know that it passes through the given point. Therefore, using point-slope form, the equation is:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Let's say the given point is (x1, y1) = (a, b). Plugging in the values, we get:

y - b = -2(x - a)

Now we can simplify:

y - b = -2x + 2a

Finally, rearranging the equation to slope-intercept form (y = mx + b), we have:

y = -2x + 2a + b

Therefore, the equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the equation y = -2x is y = -2x + 2a + b.