The slope-intercept form of a linear equation is given by y = mx + b, where m is the slope and b is the y-intercept.
So, using the given slope m = -2 and the point (-9,-5), we can substitute these values into the equation and solve for b:
-5 = -2(-9) + b
-5 = 18 + b
-5 - 18 = b
b = -23
Therefore, the equation of the line that has a slope of -2 and passes through the point (-9,-5) is y = -2x - 23.
Write an equation, in slope-intercept form, of a line that had a slope of -2 and passes through the point (-9,-5).
1 answer