Write an equation in ponit slope form of the line through the given ponit and with the given slope (-2,3) ; m = -2 show your work

Answer 1

The point-slope form of a linear equation is:

y - y1 = m(x - x1)

Given point: (-2, 3)
Given slope: m = -2

Substitute the values of the point and slope into the point-slope form:

y - 3 = -2(x - (-2))

y - 3 = -2(x + 2)

y - 3 = -2x - 4

y = -2x - 1

Therefore, the equation in point-slope form of the line through the point (-2, 3) with slope m = -2 is y = -2x - 1.