A(-3,-3), M(x,y), B(5,6).
x = (-3+5) / 2 = 1.
y = (-3+6) / 2 = 1 1/2 = 3/2.
The slope of a straight line is the same at all points on the line.
m = (6-(-3)) / (5-(-3)) = 9/8.
m2 = -8/9 = Negative reciprocal of m.
(1,3/2),(x,y),
m2 = (y-3/2) / (x-1) = -8/9,
Cross multiply:
y-3/2 = -8/9(x-1).
Write an equation in point slope form for the perpendicular bisector of the segment with endpoints A(-3,-3) and B(5,6)
3 answers
write an equation in point-slope form for the perpendicular bisector of the segment with the given end points M(-5,4),N(1,-2)
k/g