Write an equation for the surface area of both triangular bases of the net.

(1 point)
Responses

SA=(12)(5)(6.5)
upper S upper A equals left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 5 right parenthesis left parenthesis 6.5 right parenthesis

SA=12(3.5)(5)
upper S upper A equals Start Fraction 1 over 2 End Fraction left parenthesis 3.5 right parenthesis left parenthesis 5 right parenthesis

SA=2(12)(6.1)(3.5)
upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 6.1 right parenthesis left parenthesis 3.5 right parenthesis

SA=2(12)(3.5)(5.5)

1 answer

SA = 2(12)(3.5)(5.5)