Write an equation for the surface area of both triangular bases of the net. measurements: 5 ft. 6.5 ft. 5 ft. 5.5 ft. 6.5 ft. 5 ft. 3.5 ft 5 ft.
responses:
SA=2(1/2)(3.5)(5.5)
upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 3.5 right parenthesis left parenthesis 5.5 right parenthesis
SA=(1/2)(5)(6.5)
upper S upper A equals left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 5 right parenthesis left parenthesis 6.5 right parenthesis
SA=1/2(3.5)(5)
upper S upper A equals Start Fraction 1 over 2 End Fraction left parenthesis 3.5 right parenthesis left parenthesis 5 right parenthesis
SA=2(1/2)(6.1)(3.5)
3 answers
SA=2(1/2)(6.1)(3.5)
explain why
The surface area of a triangular base can be calculated using the formula for the area of a triangle: A = 1/2 bh, where b is the base of the triangle and h is the height of the triangle. In the case of the net provided, the triangular bases have varying measurements for their base and height.
For the net with measurements 5 ft and 6.5 ft, the surface area of one triangular base would be 1/2(5)(6.5). Since the net has two triangular bases, the total surface area for both triangular bases would be 2(1/2)(5)(6.5), which simplifies to 32.5 square feet.
The other calculations provided do not match the measurements given for the net provided, so the correct equation is 2(1/2)(6.1)(3.5).
For the net with measurements 5 ft and 6.5 ft, the surface area of one triangular base would be 1/2(5)(6.5). Since the net has two triangular bases, the total surface area for both triangular bases would be 2(1/2)(5)(6.5), which simplifies to 32.5 square feet.
The other calculations provided do not match the measurements given for the net provided, so the correct equation is 2(1/2)(6.1)(3.5).
4 answers