Write an equation for the ellipse foci (9,0) and x intercepts (15,0)

Answer 1

The general form of the equation for an ellipse with foci (h,k), x intercepts (a,0) and (b,0) is:

(x-h)^2 / a^2 + (y-k)^2 / b^2 = 1

Given that the foci are at (9,0) and the x intercepts are at (15,0), we have:

(h,k) = (9,0)
(a,0) = (15,0)

Plugging these values into the equation, we get:

(x-9)^2 / 15^2 + y^2 / b^2 = 1

Simplifying:

(x-9)^2 / 225 + y^2 / b^2 = 1

Therefore, the equation of the ellipse with foci (9,0) and x intercepts (15,0) is:

(x-9)^2 / 225 + y^2 / b^2 = 1