Write an equation for a cosecant function with a period of 3𝜋 and a range of (−�‡,−2]�¾[2,�‡)

Answer 1

so you want y = a csc (2/3)x
where a is whatever your (−�‡,−2]�¾[2,�‡) means

well, y = csc (2x/3) looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+csc+(2x%2F3)

the vertical lines are asymptotes at
x = 0, ±3π/2, ± 3π, ...
the range is y ≥1 OR y ≤ -1