write an eqaution in slope-intercept form of the trend line (50, 1) (35, 0.8) (29, 1) (35, 0.8) (15, 0.9) (21, 0.9)

Answer 1

To find the equation of the trend line in slope-intercept form, we first need to calculate the slope using two of the given points. Let's use the points (50, 1) and (35, 0.8) to find the slope:

slope = (0.8 - 1) / (35 - 50)
slope = (-0.2) / (-15)
slope = 0.0133

Now that we have the slope, we can use it along with any of the given points to find the y-intercept. Let's use the point (50, 1):

1 = 0.0133(50) + b
1 = 0.665 + b
b = 0.335

Now we can write the equation of the trend line:

y = 0.0133x + 0.335

Therefore, the equation of the trend line in slope-intercept form is y = 0.0133x + 0.335.