444= 4+4+4=12
381=3+8+1=12
453=4+5+3=12
Write all possible 3-digit numbers sum of whose digits is 12
2 answers
1+11, so 129 138 147 156 and all their permutations
2+10, so 219 228 237 246 255 ...
and so on
2+10, so 219 228 237 246 255 ...
and so on