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or Write a system of equations to describe the situation below, solve using any method, and fill in the blanks. Linda and her f...Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
Jada and her friend Laura are each baking apple pies and tarts for a bake sale, using the same recipes. Jada baked 8 apple pies and 1 apple tart, using a total of 70 apples. Laura made 3 apple pies and 5 apple tarts, which used 54 apples. How many apples does each dessert require?
An apple pie uses
apples and an apple tart requires
apples.
Jada and her friend Laura are each baking apple pies and tarts for a bake sale, using the same recipes. Jada baked 8 apple pies and 1 apple tart, using a total of 70 apples. Laura made 3 apple pies and 5 apple tarts, which used 54 apples. How many apples does each dessert require?
An apple pie uses
apples and an apple tart requires
apples.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To set up a system of equations for the problem, we can define:
- Let \( p \) be the number of apples needed for one apple pie.
- Let \( t \) be the number of apples needed for one apple tart.
Now we can create equations based on the information given:
For Jada:
- She baked 8 apple pies and 1 apple tart, which used a total of 70 apples. This gives us our first equation:
\[
8p + 1t = 70 \tag{1}
\]
For Laura:
- She made 3 apple pies and 5 apple tarts, which used a total of 54 apples. This gives us our second equation:
\[
3p + 5t = 54 \tag{2}
\]
Now we have the following system of equations:
1. \( 8p + t = 70 \)
2. \( 3p + 5t = 54 \)
Next, we can solve this system using substitution or elimination. Let's use substitution with the first equation. From equation (1), we can express \( t \) in terms of \( p \):
\[
t = 70 - 8p \tag{3}
\]
Now, substitute equation (3) into equation (2):
\[
3p + 5(70 - 8p) = 54
\]
Distribute \( 5 \) in the equation:
\[
3p + 350 - 40p = 54
\]
Combine like terms:
\[
-37p + 350 = 54
\]
Subtract 350 from both sides:
\[
-37p = 54 - 350
\]
\[
-37p = -296
\]
Now, divide by -37:
\[
p = \frac{296}{37} = 8
\]
So, each apple pie requires \( 8 \) apples.
Next, we substitute \( p \) back into equation (3) to find \( t \):
\[
t = 70 - 8(8)
\]
\[
t = 70 - 64
\]
\[
t = 6
\]
Thus, each apple tart requires \( 6 \) apples.
Summarizing our results, we have:
An apple pie uses **8** apples and an apple tart requires **6** apples.
- Let \( p \) be the number of apples needed for one apple pie.
- Let \( t \) be the number of apples needed for one apple tart.
Now we can create equations based on the information given:
For Jada:
- She baked 8 apple pies and 1 apple tart, which used a total of 70 apples. This gives us our first equation:
\[
8p + 1t = 70 \tag{1}
\]
For Laura:
- She made 3 apple pies and 5 apple tarts, which used a total of 54 apples. This gives us our second equation:
\[
3p + 5t = 54 \tag{2}
\]
Now we have the following system of equations:
1. \( 8p + t = 70 \)
2. \( 3p + 5t = 54 \)
Next, we can solve this system using substitution or elimination. Let's use substitution with the first equation. From equation (1), we can express \( t \) in terms of \( p \):
\[
t = 70 - 8p \tag{3}
\]
Now, substitute equation (3) into equation (2):
\[
3p + 5(70 - 8p) = 54
\]
Distribute \( 5 \) in the equation:
\[
3p + 350 - 40p = 54
\]
Combine like terms:
\[
-37p + 350 = 54
\]
Subtract 350 from both sides:
\[
-37p = 54 - 350
\]
\[
-37p = -296
\]
Now, divide by -37:
\[
p = \frac{296}{37} = 8
\]
So, each apple pie requires \( 8 \) apples.
Next, we substitute \( p \) back into equation (3) to find \( t \):
\[
t = 70 - 8(8)
\]
\[
t = 70 - 64
\]
\[
t = 6
\]
Thus, each apple tart requires \( 6 \) apples.
Summarizing our results, we have:
An apple pie uses **8** apples and an apple tart requires **6** apples.
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