Let \( x \) be the number of rides Diane goes on.
We can set up the following equations for the two options:
- Cost of unlimited rides: \( C_1 = 40 \)
- Cost of admission plus rides: \( C_2 = 16 + 1x \)
To find out when the costs are the same, we set \( C_1 \) equal to \( C_2 \):
\[ 40 = 16 + 1x \]
Now, we can solve for \( x \):
- Subtract 16 from both sides:
\[ 40 - 16 = x \]
- This simplifies to:
\[ 24 = x \]
So, Diane can go on 24 rides.
Next, we find out the cost for both options when she goes on 24 rides:
For the unlimited rides option:
\[ C_1 = 40 \]
For the admission plus rides option:
\[ C_2 = 16 + 1(24) = 16 + 24 = 40 \]
Therefore, both options cost the same.
To fill in the blanks:
If Diane goes on 24 rides, the two options will both cost $40.