The parametric equations show us two direction vectors in the plane, namely
[-2,3,-1] and [2,1,-2]
using those two we can find a normal, I will assume you know how to do that, I got
[5,6,8)
To the scalar equation would be
5x + 6y + 8z + c = 0
but (3,1,5) is a point on it, so
15 + 6 + 40 + c = 0
c = -61
equation: 5x + 6y + 8z - 61 = 0
Write a scalar equation of each plane, given its parametric equations.
x = 3 - 2s + 2t
y = 1 + 3s + t
z = 5 - s - 2t
1 answer