Asked by Sam
Write a quadratic function rule for the given table in problems 4 and 5.
4. X (0, 1, 2, 3)
Y (-6, -5, -7, 3)
a. y= x-6
b. y= x-4
c. y= x^2 - 3
d. y= x^2 - 6
5. X(-1, 0, 1, 7)
Y(5,4,5,8)
a.y=x+4
b.y=x^2+4
c.y= x^2+6
d.y=x+6
4. X (0, 1, 2, 3)
Y (-6, -5, -7, 3)
a. y= x-6
b. y= x-4
c. y= x^2 - 3
d. y= x^2 - 6
5. X(-1, 0, 1, 7)
Y(5,4,5,8)
a.y=x+4
b.y=x^2+4
c.y= x^2+6
d.y=x+6
Answers
Answered by
Steve
#4 cannot be correct
y increases, then decreases, then increases again.
However, if y(2) = -2, y = x^2-6
For #5, clearly (a) and (b) are out.
Since 5 = 1+4, (c) must be correct, but there is a other huge typo. y(2) = 8, NOT y(7)
y increases, then decreases, then increases again.
However, if y(2) = -2, y = x^2-6
For #5, clearly (a) and (b) are out.
Since 5 = 1+4, (c) must be correct, but there is a other huge typo. y(2) = 8, NOT y(7)
Answered by
Jason
C
A
D
D
C
^^ answers. 100%
A
D
D
C
^^ answers. 100%
Answered by
Bea miller
No it's
C
A
D
D
B
These are for all connections student good luck
C
A
D
D
B
These are for all connections student good luck
Answered by
Butter Man
thank you bea miller :)
Answered by
Anon
sam you had a typo in .4 you wrote -7 it was -2 and bea miller is correct 100%
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